How do you graph a quadratic function example?

Example: The vertex of the parabola y = 7(x – 1)² – 2 is (1, -2). The graph opens upward, so the vertex is the minimum point of the parabola. Example: The vertex of the parabola y = -2(x – 7)² + 4 is (7, 4). The graph opens downward, so the vertex is the maximum point of the parabola.

How do you write the equation of a parabola Khan Academy?

Given the focus (h,k) and the directrix y=mx+b, the equation for a parabola is (y – mx – b)^2 / (m^2 +1) = (x – h)^2 + (y – k)^2.

What is a graph of quadratic function called?

The graph of a quadratic function is called a parabola and has a curved shape. One of the main points of a parabola is its vertex.

How do you graph standard form?

First, find the intercepts by setting y and then x equal to zero. This is pretty straightforward since the line is already in standard form. Plot the x and y-intercepts, which in this case is (9,0) and (0,6) and draw the line on the graph paper!

How do you write an equation given two points?

Find the Equation of a Line Given That You Know Two Points it Passes Through. The equation of a line is typically written as y=mx+b where m is the slope and b is the y-intercept.

How do you write an equation of a line?

The slope-intercept form of a linear equation is written as y = mx + b, where m is the slope and b is the value of y at the y-intercept, which can be written as (0, b). When you know the slope and the y-intercept of a line you can use the slope-intercept form to immediately write the equation of that line.

What is the equation of this graphed line?

To find the equation of a graphed line, find the y-intercept and the slope in order to write the equation in y-intercept (y=mx+b) form. Slope is the change in y over the change in x. Find two points on the line and draw a slope triangle connecting the two points.

How do you write the standard form of a hyperbola?

The standard form of a hyperbola that opens sideways is (x – h)^2 / a^2 – (y – k)^2 / b^2 = 1. For the hyperbola that opens up and down, it is (y – k)^2 / a^2 – (x – h)^2 / b^2 = 1. Notice that the x appears first for the hyperbola that opens sideways and the y appears first for the hyperbola that opens up and down.