## What is the KF?

Kf is the molal freezing point depression constant of the solvent (1.86 °C/m for water). m = molality = moles of solute per kilogram of solvent.

## What is KF of NaCl?

Kf is the molal freezing point depression constant for the solvent, and. m is the molality of the solution. Step 1: Calculate the molality of the NaCl. moles of NaCl=31.65g NaCl ×1mol NaCl58.44g NaCl =0.5416 mol NaCl.

## What is the KF of glucose?

Kf=1.86∘C⋅kgmol is the freezing point depression constant of water. mi is the molality, mol solutekg solvent , of the solute glucose in the solvent water.

## What is the KF of camphor?

The freezing point of camphor is 178.4 C and its molar freezing point depression constant (Kf) is 37.7 C kg/mol.

## Is KF acid or base?

KF is a salt of a strong base (KOH) and a weak acid (HF).

## What is KF solubility?

Solubility in water. anhydrous: 92 g/100 mL (18 °C) 102 g/100 mL (25 °C) dihydrate: 349.3 g/100 mL (18 °C)

## Is KF soluble in water?

KF is highly soluble in water. It initially dissociates into K+ and F-.

## How do you calculate delta TB?

512 Degree C/molality Bp Solution = 97.2 Degree C Calculate Delta Tb Delta Tb = BP Solution – BP Solvent Delta Tb = 97.2-100 = -2.8 Calculate M Delta Tb/ikb M = Delta Tb/l Times Kb M =-2.8/1 Times 512 Degree C/m M = -3.31 Mol/kg.

## How do you calculate KF in water?

Divide the freezing point depression by the molal concentration so you have: Kf = delta Tf / cm. Insert the values for delta Tf and cm. For instance, if you have a solution with a molality of 0.455 which freezes at 3.17 degrees Celsius, then Kf would equal 3.17 divided by 0.455 or 6.96 degrees Celsius.

## What is the freezing point of KCL?

770 °C

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The freezing point depression ∆T = KF·m where KF is the molal freezing point depression constant and m is the molality of the solute. Rearrangement gives: mol solute = (m) x (kg solvent) where kg of solvent is the mass of the solvent (lauric acid) in the mixture.

## What is the KF of benzoic acid?

2. Calculate molality (m), in mol/kg, using the formula, ∆t = Kf • m (Kf = 3.9°C-kg/mol for lauric acid). Calculate the experimental molecular weight of benzoic acid, in g/mol. Use the original mass of benzoic acid from the Data and Calculations table, and the moles of benzoic acid you found in the previous step.

## What is the kb of benzene?

Kb(benzene) = 2.53 °C/m In A Laboratory Experiment, Students Synthesized A New Compound And Found That When 14.35 Grams Of The Compound Were Dissolved In 215.6 Grams Of Benzene, The Solution Began To Boil At 80.575 °C. The Compound Was Also Found To Be Nonvolatile And A Non-electrolyte.

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